3x^2+x-1/12=0

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Solution for 3x^2+x-1/12=0 equation: 


x in (-oo:+oo)

3*x^2+x-(1/12) = 0

3*x^2+x-1/12 = 0

3*x^2+x-1/12 = 0

DELTA = 1^2-(-1/12*3*4)

DELTA = 2

DELTA > 0

x = (2^(1/2)-1)/(2*3) or x = (-2^(1/2)-1)/(2*3)

x = (2^(1/2)-1)/6 or x = (-(2^(1/2)+1))/6

x in { (-(2^(1/2)+1))/6, (2^(1/2)-1)/6 }

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